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x^2-14.7x+32=0
a = 1; b = -14.7; c = +32;
Δ = b2-4ac
Δ = -14.72-4·1·32
Δ = 88.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14.7)-\sqrt{88.09}}{2*1}=\frac{14.7-\sqrt{88.09}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14.7)+\sqrt{88.09}}{2*1}=\frac{14.7+\sqrt{88.09}}{2} $
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